Pixivwkxt

Are solved by group of students and teacher of Class 9, which is also the largest studentExample Solve 8a 3 27b 3 125c 3 – 90abc Solution This proceeds as Given polynomial (8a 3 27b 3 125c 3 – 90abc) can be written as (2a) 3 (3b) 3 (5c) 3 – 3(2a)(3b)(5c) And this represents identity a 3 b 3 c 3 3abc = (a b c)(a 2 b 2 c 2 ab bc ca) Where a = 2a, b = 3b and c = 5c Now apply values of a, b and c on the LHS of identity ie a 3 b 3 c 3Jun 02,  · Factorisea^3 b^3 C^3 3abc Get the answer to this question by visiting BYJU'S Q&A Forum If A B C 0 Then A 3 B 3 C 3 0 How Quora A^3+b^3+c^3-3abc formula proof